Both the E-DR and the L-DR participants had normal retinal hemodynamic measurements at steady state (
Table 3). In contrast, in response to the challenge imposed by the postural change from sitting to reclining, the E-DR group showed abnormalities not shown by the L-DR group (see
Fig.). The E-DR group failed to constrict the diameter of the retinal artery in response to pressure: among the five participants, four showed paradoxical dilation and one normal constriction; and this pattern was different from both the pattern of the control group (
P = 0.005) and the L-DR group (
P = 0.020). The L-DR group was not significantly different from the control group, with six of the seven L-DR participants constricting normally and one showing dilation. The E-DR participants manifested a defective myogenic response despite the fact that the changes in systemic BP and OPP while reclining were similar to those in the other groups. The reclining systolic and diastolic BP were, respectively (in mm Hg), 99 ± 11 and 55 ± 8 in controls, 95 ± 2 and 58 ± 6 in the E-DR participants, and 94 ± 10 and 57 ± 7 in the L-DR participants. The OPP while reclining, estimated from mean arterial pressure (MAP)
reclining – IOP,
7,12 was (in mm Hg) 55 ± 9 in controls, 51 ± 5 in the E-DR participants, and 49 ± 5 in the L-DR participants. Consequently, the increase in OPP induced by reclining, which represents the driving stimulus for the myogenic arterial constriction, was similar in all groups: 15% (11%–20%) in the controls, 15% (9%–26%) in the E-DR group, and 21% (10%–30%) in the L-DR group (
P = NS). The blood speed response to reclining was especially variable among the L-DR participants, but did not differ among the groups. In agreement with the fact that blood flow is the product of the arterial diameter and blood speed, the lack of diameter constriction in the E-DR group resulted in an abnormally increased retinal blood flow (
P = 0.016 versus controls). In contrast, in the L-DR group, the blood flow changes were not different from controls (
P = 0.60).